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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 11:56:43 IST
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a point charge is placed at rest inside a thin metallic spherical shell, but not at its centre. a) the force acting on the charge is zero b) the force acting on the charge is non zero c) the force acting on the particle is non zero constant, wherever the charge is placed inside the shell d) none of these
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 13:53:06 IST
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HEY, I GUESS IT IS ZERO.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 13:55:04 IST
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its 0...no field inside shell even if there is external fields etc
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 15:14:08 IST
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sorry its not 0
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Answer should be (b)
The charge distribution should be nonuniform which makes force non zero
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 21:55:42 IST
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charge appears on the INSIDE SURFACE of the shell......but how to know is it uniform or not??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 22:08:02 IST
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its 0 (zero)
as there is electrostatic shielding inside the conductor so E = 0
also F = qE = 0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 22:22:26 IST
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but there exists electric field inside the shell...due to the charge appeared...so it should exert a force on the charge....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Mar 2008 22:28:35 IST
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it shud be b) because the charge distribution on the inner surface of shell will be non-uniform and the portion of shell which is closer to the charge will determine direction of force
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2008 22:32:25 IST
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i think edison overlooked the fact that the charge is inside it
BUT NOT AT ITS CENTRE
so ans is B
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2008 22:36:35 IST
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no ans is a only c consider lik this..think along the lines of electrostatic shielding... a sensitive obj placed anywhere inside cavity of conductor is protected from ne field so tht it is not affected at all now this is the same case..the field inside is only due to the charge itself..n its own cannot affect it..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Mar 2008 16:03:51 IST
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field is NOT only due to the charge...its also due to the charge of the spherical shell which has been assembled at the inside surface of the shell..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Mar 2008 16:12:54 IST
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its definately b...nishant;s reason is absolutely right..the side where the charge is closer to it will have more electric field lines than at the other end. so non-uniform field would result in force..E = 0 only when charge is at the centre.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Mar 2008 16:18:27 IST
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its surely b yar. bcz if charge will be at centre den only all forces due to it will get cancelled out. otherwise charge closer will experience more force nd remember force depend on distance
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dont worry .
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Mar 2008 19:37:29 IST
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