| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2008 21:39:39 IST
|
|
|
(1) [r =1 ] [ infinity] tan-1(1/r2) and there is no mistake in this question and explain fully.
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2008 21:45:48 IST
|
|
|
If the answer is something like tan-1(tan - tanh /tan +tanh ) where = / 2 it is probably best not to go into the solution!
|
Time wounds all heels |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2008 21:51:06 IST
|
|
|
yes you are saying absolutely write. but sir i want asolution for this problem.
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
once konichiwa had asked this problem. A few days later I was going through S L Loney Part II and I saw this problem in one of the exercises in the book. The hint involved using some infinite series about which you need not bother. Its not worth it, just take my word.
Mein sirf itna poochna chahtha hoon ki aise problem par samay vyarth kyon karte ho. Meri baat maan is qn par aur aage badhne ki koi zaroorat nahi hain
|
Time wounds all heels |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Mar 2008 22:10:50 IST
|
|
|
the infinite series of tan^-1 x ?
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 10:25:05 IST
|
|
|
Consider the expansion of  Notice that the general term is . Hence, . is a very famous result for which I have listed the proof below.
|
Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
|
this reply: 15 points
(with 3 
in 3 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 11:47:25 IST
|
|
|
TO PROVE:  PROOF: Now, the roots of occur at where  Hence we can factorise as follows: Multiply out the products and collect the coefficients of  to see that it is equal to But from the original expansion of  , the coefficient of  is Hence both are equal  .
|
Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|