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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 13:56:22 IST
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if the plane has intercept a, b, c and is at a distance m units frm the point whre the 3 mutually perp axis meet each other. then a-2 + b-2 + c-2 = ?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 14:34:54 IST
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ans : m-2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 14:37:11 IST
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eq of plane will be x\a+y\b+z\c=1 now just use dist formula and square both sides rate me if useful cheers!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 19:15:29 IST
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suppose the eq of plane is Ax+By+Cz=D now aplly the intecept conditions then apply distance formula
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 22:40:12 IST
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still didn't understand, hash include u right.
HOW? plzzzzzz explain.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 08:53:32 IST
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u will get x intercept when (a,0,0) Aa+0+0=D similarly 0+Bb+0=D 0+0+Cc=D therrefore 1/a=A/D similarly for others u apply then use distance formula D=m/root of (A2+B2+C2)
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