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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Mar 2008 17:32:28 IST
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if from a point (f,g,h)  rs PL, PM be drawn to yz &zx planes then the eqn. to the plane olm is 1. x + y - z --- ---- ----- f g h 2. x + y + z --- ---- ----- f g h 3. x - y + z --- ---- ----- f g h 4. -x + y + z --- ---- ----- f g h
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OK lets see..
The unit vector perpendicular to yz plane is i^ and the unit vector perpendicular to zx plane is j^ . So equations of line perp. to yz & zx plane and passing through P are
x-f = y-g/0 = z-h/0 and x-f/0 = y-g = z-h/0
So any points on these lines are (  + f , g , h ) and (f,  + g , h)
Now since these points intersect the above given planes, we get  = -f and = -g ( Because in yz plane x=0 and in zx plane y=0)
So finally the points are ( 0, g, h) and ( f , 0 ,h)
And you have the origin as (0,0,0).So equation of plane passing through 3 points can be found out easily now.
Answer is coming out to be OPTION A)
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
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