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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 13:59:48 IST
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Hi please 1. find the area included between the curves y^2 = 4ax and x^2 + y^2 = 8x which lies above the x axis. please do not solve just tell which area should we take draw figure and u will see that two areas are there above x axis . but which area?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 16:35:07 IST
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edit*
see shaded area
thats the only area INCLUDED between the two curves, the other one is inside circle but outside the parabola
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 17:25:10 IST
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akhil_o........ your figure is wrong.......
the circle has center (4,0) and radius 4........
so the circle and parabola must meet at the origin............
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 18:52:22 IST
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It is a very nice point u ask there.This question is very much there in CBSE NCERT text but i think the solution there is wrong . See the area enclosed between the curves (Parabola and Circle) is asked. so according to definition ,(Parts of the curves should form the boundary of the area u r going to consider). Here x axis (the way in which the question is worded is not one of the curves).It is just said "area above x axis".So actually u shud consider the small area (almost convex shaped) between the curves,and not the bigger area above x axis.(bcos if u take this then it means u r considering x axis also as one of the curves which is wrong). I think the answer so obtained is 4pi - 32/3
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 18:56:46 IST
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Akhil ..u hav said "That s the area included between the 2 curves" Now as far as i can see there are 3 curves. parabola,circle and the x axis which u have missed so the other area is actually the required area
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 19:12:19 IST
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i am sorry dude i didnt get u...
forget the x-axis for now,,, draw the figure BETWEEN the two curves, ie included in both curves since outer area u mention is OUTSIDE the parabola, i did not consider it now plug in the above-x-axis, and eliminate the loweer half of the shaded area
plz corrrect me
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 21:28:45 IST
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yes sboosy , the answer is 4pi - (32/3) ........
the figure given by akhil is correct but the shaded region is wrong.......
the required area must be the area of smaller region between the circle and the parabola (only above the x-axis)........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 21:45:17 IST
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plese explain why!
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 21:52:48 IST
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wait read the question properly ::::::::: " find the area included between the curves y^2 = 4ax and x^2 + y^2 = 8x which lies above the x axis. "
the area which you have shaded in your post is that is the larger region is " area included between y2=4ax and x2 + y2 = 8x and x-axis " the area which i have mentioned is the smaller region....... "area included between y2=4ax and x2 + y2 = 8x (only) ......... and lying above the x-axis......." understood???? for reference : this sum is in RD SHARMA page number 21.37 problem 48 ........ the answer is 4pi - 32/3 .....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2008 22:08:33 IST
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so do we always just find smaller areas unless mentioned?
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:41:27 IST
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yup friends
i also did what sboosy is saying
But i dont think that cbse is going to give us the marks for that.
not even 1 mark as our figure is wrong which is supposed to carry 1 mark but only if it is correct.(as per cbse it is wrong though!)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:42:39 IST
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i also gt the answer as
4pi - 32/3
but they will be checking it according to ncert textbook
:(
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:44:24 IST
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you should read the question very carefully..... and then you should decide whether it is the smaller area or the larger area.........
if it is already mentioned in the question (like " find the smaller area between the circle and the parabola " )there is no problem..........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:46:51 IST
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No nothing is mentioned. But I had the same doubt too.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:50:11 IST
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