| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:30:06 IST
|
|
|
if a b c are 3 vectors such that (b.c).a=(a.b).c . what does this imply?
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:31:51 IST
|
|
|
Associative and commutative laws holds good.
|
    
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:32:12 IST
|
|
|
it doesnt imply anything. this is just a combination of associative law and commutative law for dot droduct of vectors, which is ALWAYS true.. so a,b,c can be any 3 vectors..
|
JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
join the revolution!! |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:35:40 IST
|
|
|
Hey shrids that's what I meant.
|
    
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:39:07 IST
|
|
|
the associative law for dot product does not exist as b.c would be a scalar(d) and the dot product of a scalar with a vector is not defined thus d.a is not defined
|
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:40:28 IST
|
|
|
correct me if i'm wrong!
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 12:42:28 IST
|
|
|
Yes correct.
|
    
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 15:03:57 IST
|
|
|
how can (b.c).a even exist or be a legal expression???the statement is wrong!!!!
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 17:20:58 IST
|
|
|
yes how can u have a dot product between a scalar and a vector,its just normal multipication. !!!!!!!!!!!
|
Varsha
be cool,
tomorrow is what we make it today,
so if u can dream it , u can make it .
life is an ice cream ,eat it before it melts away!!!!!!!!!
    

|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 19:12:58 IST
|
|
|
but even if it is normal multiplication, can it exist??
|
Remember Cedric. Remember, if the time should come when you have to make a choice between what is right and what is easy, remember what happened to a boy who was good, and kind, and brave, because he strayed across the path of Lord Voldemort. Remember Cedric Diggory.
Albus Dumbledore
Goblet of Fire, Chapter 37, Page 724
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 19:21:04 IST
|
|
|
in vectors there are 2 multiplications '.' and 'x' wat do u mean by 'normal' multiplication??? pls make ur question clear
|
Nitwit Blubber Odment Tweak
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 19:28:51 IST
|
|
|
i think she means n times magnitude into a vector. a vector 3a vector etc. jus telling u wht i think she meant
|
---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 20:08:11 IST
|
|
|
(a.b).c =(abcosQ).c=abcosQ ccosQ' so why all are saying it does not exist
correct me if i m wrong or rate me if useful
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 20:13:44 IST
|
|
|
a.b is a scalar.. dot product of 2 vectors is a scalar u cannot take the 2nd dot pdt as it will then amt to dot pdt between a scalar and a vector
|
Nitwit Blubber Odment Tweak
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 20:16:02 IST
|
|
|