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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Mar 2008 21:57:51 IST
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sin(eX)=2X+2-x then find the number of real solutions?
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30 Mar 2008 22:00:41 IST
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RHS minimum value=2 at x=0
LHS max value=1
so no solution
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" Always remember money isn't everything but make sure you have made a lot of it before talking such nonsense!"
- Bill Gates |
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30 Mar 2008 22:01:45 IST
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"I a universe of atoms.......an atom in the universe" |
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30 Mar 2008 22:02:15 IST
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oh sorry akhil....dint know you were at it.
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"I a universe of atoms.......an atom in the universe" |
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1 Apr 2008 19:57:33 IST
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no solution because sin(eX) has the range from [-1,1]
whereas 2X+2-x has the least value of 2.
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