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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 13:28:30 IST
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Q A thin spherical shell of radius R is set into the rotation abt its axis at an angular speed  .This rotating wheel is now placed on a rough surface (horizontal) wid its axis horizontal. Because of friction at the contact , thw wheel accl forward & its rotation .declerateas till the wheel starts pure rolling on the surface .Find the linear speed of the wheel after it starts pure rolling?????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 17:57:57 IST
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some1 plsssss solve this
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 17:59:32 IST
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Conserve angular momentum abt lowermost point
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 18:08:27 IST
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elastiboysai is right ...here's the soln, since the torque abt pt of contact is zero ang momentum is conserved abt tht pt initial ang momentum=2/3mr2  final ang momentum=5/3mr2 ' .`. ' = 2/5 or linear speed v=2/5 r
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Ajay Antony |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 18:09:01 IST
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Abt bottommost point net torque is zero so u can conserve angular momentum abt lowermost point. suppose inital angular veloc is  and final angular veloc is 0 I =I 0 +mrv and once pure rollin starts v=r 0 plug in for I and solve 2/3mr^2 =5/3mr^2 0
0=2/5 so v=2/5 0r
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