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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 15:54:25 IST
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16 persons are occupying seats round a table.if every person refuses to work with any one of his neighbours,in how many ways can a committee of 6 can be made with those persons under chairmanship of a particular person
pls answer with explanation
answer is 126
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31 Mar 2008 21:26:50 IST
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There are 6 gaps into which 10 people have to be put . each of the gaps should have atleast 1 person.
this is equal to the no . of positive solutions to the equation :
x1 + x2 + .... + x6 = 10
So answer = 10-1C6-1 = 126.
Note that the chairman is given so he will not change. if u put the solutions of x1 , x2 ... into the gaps , it will correspond to exactly 1 solution.
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this reply: 15 points
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