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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 20:44:35 IST
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find the 7th root of 7^(7^7)
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31 Mar 2008 20:46:36 IST
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7^7^6 ????
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31 Mar 2008 20:48:12 IST
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scroll down
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31 Mar 2008 20:49:36 IST
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i agree with aditya, 7^7^6
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31 Mar 2008 21:21:27 IST
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[ 7] 7 7.7 7.7 7.7 7.7 7.7 7.7 7 = 7 7 is it not the ans. i did not see the ( )
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31 Mar 2008 21:37:29 IST
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ans is 7^7
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31 Mar 2008 21:39:20 IST
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check it with anyone
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31 Mar 2008 21:42:32 IST
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yeah,sandy is rite
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31 Mar 2008 21:47:06 IST
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nope !! take ( 7^7 ) = m so we are to find ( 7^m) ^( 1/7 ) = 7 ^ ( 7 ^7 /7 ) = 7^ ( 7^6 )
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31 Mar 2008 21:47:33 IST
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7^(7^7) and (7^7)^7 are different .
(7^7)^7 = 7^49 . The seventh root of this no. is 7^7.
But the question asked is 7^(7^7)
It's 7th root is 7^[(7^7)/7] which is equal to 7^(7^6)
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31 Mar 2008 21:48:46 IST
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learn prop of exponentials
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31 Mar 2008 21:49:16 IST
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yeah sry.its 7^(7^6)
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31 Mar 2008 21:53:27 IST
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i never notised the ( )
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31 Mar 2008 21:59:21 IST
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no it is 7^7
since 7th root
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