| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 20:44:58 IST
|
|
|
Q) Is magnetic force conservative?
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 20:46:55 IST
|
|
|
nope according to maxwell they arent..... but potential is defined for them.... dont ask me why... my prof told me that it can be answered on basis of maxwells eqn....
|
FAILURE IS NOT FALLING IN LIFE BUT NOT RISING AGAIN AFTER FALLING!!!!!!
I LIKE WAVES NOT BECAUSE THEY RISE AND FALL..
BUT BECAUSE EVERYTIME THEY FALL THEY RISE AGAIN!!!!!!!
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 20:50:54 IST
|
|
|
Well I don,t know, But i think it is By definition they are for the work done is independent of the path. As long as that condition is met with you can call it conservative. Else what does it implies being conservative.
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 20:53:47 IST
|
|
|
no never u conserve only torque due it therefore
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 20:57:06 IST
|
|
|
as far as jee is concerned i guess u can consider it to be conservative
|
FAILURE IS NOT FALLING IN LIFE BUT NOT RISING AGAIN AFTER FALLING!!!!!!
I LIKE WAVES NOT BECAUSE THEY RISE AND FALL..
BUT BECAUSE EVERYTIME THEY FALL THEY RISE AGAIN!!!!!!!
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 20:59:28 IST
|
|
|
yes it is..
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 21:23:51 IST
|
|
|
no ! it is not conservative . I can give u a simple example . Consider an infinitely long current carrying wire carrying a current I . This produces a magnetic field B = (  oI / 2 pi r ) e Now if u consider the line integral B.dl ( contour being a circle of radius r ) its value is =  o I (can be obtained directly from ampere's law for any contour ) which is non - zero . The integral signifies work done in carrying a fictiuous unit pole carrying round the wire . Since this work is non - zero , B field is non conservative .
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 02:58:03 IST
|
|
|
Since i don't see many more comments on the topic, i thought of adding this. Though the line integral of magnetic field over a closed loop is not zero it is considered a conservative field. Ofcourse there are some disagreements. But since isolated monoples do not exist. The significance of line integral of magnetic field has little to do with the energy transactions of an object moving within a magnetic field. Usually the conservative nature of the magnetic field is demonstrated as in case of motion of a charged particle in a magnetic field.
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 07:35:30 IST
|
|
|
bt in jee do we have to consider it to be conservative??
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|