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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 09:57:18 IST
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Minimum value of angle "A" for which ray incident on mirror parallel to principle axis suffers more than ONE reflections is.......
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 10:42:59 IST
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solving....wait Yes i do believe it is pi/2
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 10:50:27 IST
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oh how can it be pie/2?? cant it be less thn it??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 11:08:08 IST
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gaurav the ans given here is 45 degree bt hw?
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the extreme case is the light ray falls on 1 extreme end and the 2nd reflection takes place @ other extreme
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Nitwit Blubber Odment Tweak
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 11:47:46 IST
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OH yes that was what my diagram was... lol i didnt realise it's 45 degrees
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 11:51:42 IST
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Since any ray parallel to principal ray will pass through the focus, look for a possible configuration which will need minimum mirror length and the ray will touch the mirror again on passing through focus.. computer's diagram is right :) i just didnt think carefully wt the angle was :)
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 15:26:50 IST
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thnx both of u
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