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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 12:38:05 IST
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Two small balls A and B , each of mass m, are joined rigidly by a light horizontal rod of length L.The rod is clamped at the center in such a way that it can rotate freely about a vertical axis through its center. The system is rotated with an angular speed w about the axis. A particle P of mass m kept at rest sticks to the ball A as the ball collides with it. Find the new angular speed of the rod?
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1 Apr 2008 12:49:45 IST
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Edit:Made a silly mistake...
@conjurer-I had visualized the question wrongly.
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MaNuTd RoXxXx..MaNuTd 2 WiN PrEmIeR LeAgUe ThIs SeAsOn ToO AlOnG WiTh ChAmPiOnS LeAgUe.....HaiL RoNaLdO ...HaiL LaMpArD... |
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1 Apr 2008 13:08:32 IST
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Just conserve energy as there is no net external force.
Initially energy = m(L/2)^2 * w^2
Final energy = 3/2 * m(L/2)^2 * W^2
Equating we get 2/3w^2 = W^2
W = root(2/3)w
@LAMPARD: Is there any way that the angular velocity increases?
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