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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 13:45:48 IST
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f(x) is
-2 <= x < = -1 {x}
-1 < x <=1 signum function
1<x<=2 {-x}
given : -2 is pt of discontinuity but i feel no. plot graph.
verify if i'm right.
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1 Apr 2008 14:14:25 IST
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if f(x) is not equal to fraction of x and is equal to just 'x' then the function is discontinuous at '0' and '1'
If the function is fraction of x then it is discontinuous at '-1',0, and '1'.
Since u don't know the definition of function on the other side u can't comment on the continuity at '-2'.
~Cheerio!!!
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4 Apr 2008 16:29:53 IST
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thanks.
it came in BMAT.
they took -2 as discontinuous pt.
are they rite?
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