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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2008 16:52:59 IST
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a proton of charge e enters B = B0 i initial velocity V = V0x i + V oy j
after time t y component will b V oy cos (qbt/m)
please explain
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4 Apr 2008 17:57:21 IST
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y component should not change, it is perpendicular to the magnetic field
just solve qbt/m ,
put t=2 pie m/ Bq
it comes 2pie
and cos2pie =1
so the answer is Voy
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9 Apr 2008 18:19:27 IST
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thats precisely what i thought. ans was given like this. any one else?
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