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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2008 19:41:48 IST
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the electric field at a point associated with a light wave is E=(100V/m)sin[(3 * 10^15)t] sin[(6 * 10^15)t]. If this light falls on a metal surface having a work function of 2eV, what will be the maximum kinetic energy of the photoelectrons?
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4 Apr 2008 19:47:18 IST
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he he good question!!
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4 Apr 2008 19:47:59 IST
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sum1 reply.............
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4 Apr 2008 20:13:18 IST
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cumon guye, dont let me down................
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4 Apr 2008 20:18:26 IST
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this is easy
from the given eqn. u can get the frequency (f) of incident radiation
then
k.e. = hf - w
one more point
since the above eqn. is in form of 2 sin functions
rewrite it by using 2sin a.sinb = sin (a +b).sin(a - b)
rate me
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all the best ... |
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4 Apr 2008 20:22:03 IST
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wat arpan told is right...
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FAILURE IS NOT FALLING IN LIFE BUT NOT RISING AGAIN AFTER FALLING!!!!!!
I LIKE WAVES NOT BECAUSE THEY RISE AND FALL..
BUT BECAUSE EVERYTIME THEY FALL THEY RISE AGAIN!!!!!!!
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