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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Solve
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[Post New]6 Apr 2008 14:32:55 IST
    Subject: Solve
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rahulraj1 (14)

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(ey+1)cos XdX+ eysinXdy=0
    
[Post New]6 Apr 2008 14:35:45 IST
    Subject: Solve
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avi_1214545 (974)

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just separate them u'll get

cotxdx=-eydy/(ey+1)
then integrate both sides
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[Post New]6 Apr 2008 14:36:51 IST
    Subject: Re:Solve
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LAMPARD (1142)

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Open the brackets to get
eycosxdx+eysinxdy+cosxdx=0
The above exp. can be written as
d(eysinx)+cosxdx=0
Integrating throughout,
eysinx+sinx=c where c is constant.
MaNuTd RoXxXx..MaNuTd 2 WiN PrEmIeR LeAgUe ThIs SeAsOn ToO AlOnG WiTh ChAmPiOnS LeAgUe.....HaiL RoNaLdO ...HaiL LaMpArD...
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[Post New]7 Apr 2008 12:30:11 IST
    Subject: Re:Solve
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varshavallig (798)

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(e^y+1)cosxdx=e^y sinxdy
-cosx/sinx dx  =  e^y/(e^y+1) dy
-cotx dx  = e^y/e^y+1  dy
integrating,
log(e^y+1)=-log(sinx*c)
soln:
=>e^y+1+(sinx) * c =0
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