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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 14:52:23 IST
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dy/dx=x2e-3y,given that y=0 when x=0
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6 Apr 2008 15:10:05 IST
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The exp. can be written as
e3ydy=x2dx
Now integrate both sides to get
(1/3)e3y=(x3/3)+c
Now,subst. x=0 and y=0 to get the value of c.
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