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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 10:59:45 IST
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1.How is a compound named as D or L ? ( please explain in detail) (rates assured)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 11:26:22 IST
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reply karo yaar!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 11:29:41 IST
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The last chiral center in an aldose chain (farthest from the aldehyde group) was chosen by Fischer as the D / L designator site. If the hydroxyl group in the projection formula pointed to the right, it was defined as a member of the D-family. A left directed hydroxyl group (the mirror image) then represented the L-family. Fischer's initial assignment of the D-configuration had a 50:50 chance of being right, but all his subsequent conclusions concerning the relative configurations of various aldoses were soundly based. In 1951 x-ray fluorescence studies of (+) tartaric acid, carried out in the Netherlands by Johannes Martin Bijvoet (pronounced "buy foot"), proved that Fischer's choice was correct. It is important to recognize that the sign of a compound's SPECIFIC ROTATION(an experimental number) does not correlate with its configuration (D or L). It is a simple matter to measure an optical rotation with a polarimeter. Determining an absolute configuration usually requires chemical interconversion with known compounds by stereospecific reaction paths.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 11:32:53 IST
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any1 who can explain in non bookish language??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 11:36:05 IST
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you see a compound in fischer projection........ see the last but one carbon atom(the one above CH2OH)....... if OH is attached right to it .... the compound is D-......... else if OH is attached to left of it... the compound is L-.........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 15:25:54 IST
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The comp r classified into d&l forms on the basis of the fact that --- in which direction the comp rotates the polar light beam
First of all verify whether the comp has chiral center then figure out a fishermen projection According to the preference order number the comp if the numbers order comes in clock wise dir it is d-form otherwise it is l-form Pre ord... 1 is given 4 comp with high atomic no. If the first case doesnt give the result{the same comp attached} then go 4 2nd If nth doesnt give refer n+1 th case But the least prefered group should b at the bottom
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 15:32:18 IST
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i suggest you to refer ncert class 12 part2 chapter carbohydrates
just basic
if the configuration of an element corresponds or is similar to that of glyceraldehyde ie lowest oxidation nmber carbon at the top and highest oxidation number carbon at the bottom ..... if CH2OH IS AT BOTTOM AND OH IS AT BOTTOM RIGHT it is assigned D else it is assigned L
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 16:57:42 IST
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c its very simple D - mean Dextro (right) rotation L - means leavo ( left) rotatory so wen v r given an optically active or inactive compound having a chiral centre , then v can check da rotation made by da compound. if it is towards left or right we 'll give da preferences acc to da At. wt of da first grp attached to it Basically it is frm H to OH Like for eg in lactic acid
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 21:03:36 IST
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chilbi u r wrong, wat is asked here is the D or L (not d or l - the dextro and laevo as u said) D or L is actually cnfiguring a compd relative to glyceraldehyde any compd that hs a config simlar to d glyceraldehyde is calld D else L
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 21:05:43 IST
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yes chilbi u are wrong
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