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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 18:08:34 IST
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one mole of a monoatomic ideal gas undergoes process a to b in PV diagram. the specific heat is
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9 Apr 2008 18:22:29 IST
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oh common koi to solve karo!!!!!!!!!
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9 Apr 2008 18:24:04 IST
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see yaar work done in the process is area under PV graph!!!
dW=integral pdv
use ideal gas eqn!!!
hope helps!!!
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9 Apr 2008 18:26:23 IST
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can u solve it for me?
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9 Apr 2008 18:27:54 IST
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is it infinity
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9 Apr 2008 18:30:11 IST
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well the ans is not infinity, its 13R/6
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9 Apr 2008 18:36:46 IST
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is the ans 13 R /6
confirm me if it is correct ...
rate me
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all the best ... |
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9 Apr 2008 18:37:45 IST
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sorry , i hadnot seen that u had typed it already
tell me if u wnt the complete solution
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all the best ... |
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9 Apr 2008 18:37:51 IST
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edit**
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There is no better feeling in this world than being a winner! |
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9 Apr 2008 18:38:22 IST
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i will rate u but please explain how u got it
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9 Apr 2008 18:41:59 IST
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see
work done by the gas from a to b = 18 pv = 27 pv / (1- x )
solving , u get x = -1/2
given gas is monoatomic, hence Cv = 3/2 R
therefore
specific heat , C = 3/2 R + R/ (1 - x )
= 3/2 R + 2/3 R
= 13 R/ 6
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9 Apr 2008 18:44:00 IST
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how 18pv=27pv/(1-x)
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9 Apr 2008 18:45:01 IST
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thts a formula.....for a process in which PVx the work done is (P1 V1 - P2 V2)/x-1 hope u got it....POLYTROPIC EQU as arpan says....
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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9 Apr 2008 18:45:14 IST
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using polytropic equation
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9 Apr 2008 18:45:26 IST
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arpan how do u got first line
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