IIT JEE , AIEEE Forum - Mathematics , Algebra

vanish_thesnowy

LET A,B,C BE THREE FINITE SETS WITH k,l,m elements respectively. If BC contains n elements, then the number of elements in the set A*(B

C).............

srini

Hey,

Is it A(B C).

arpan1

what does A(B C) mean

sugeet

qns is not clear

saurabh_reincarnated

shud b this

all elements of A part with elements of B U C

B U C no. of elements is [(l+m) -n]= B + C - Bint.C

so total no.elements shud b...

k[ (l+m)- n]

let me know the rit ans...

Cheers!!!!!!!

cuteprincess

yaa may be i am also gtng d sam ans

n(A)=k, n(B)=l, n(C)=m and n(B

C)=n

n(B

C)= n(B)+n(C)-n(B

C)
=l+m-n

Now
(A*(B

C))=k(l+m-n)

sugeet

B

C=(B)+(C)-BUC
so BUC=(l+m-n)

and ur ans is kx(l+m-n)=kl+km-kn

nisha_07

UR ANS IS k(l+m-n)

madhavedu

(l+m-n)^k.

actually u have given is a relation from A->(BUC).

no of ordered pairs is what we want.

correct na?

spideyunlimited

LET A,B,C BE THREE FINITE SETS WITH k,l,m elements respectively. If B intersection C contains n elements, then the number of elements in the set A*(B U C).............

B U C = B + C - (B intersection C)
B U C = l + m -n

and A = k

so the number of elements in the set A*(B U C) :
= k ( l + m - n)

vanish_thesnowy

BUT ITS DIFFERENT.

spideyunlimited

umm what?

Ankur_1

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