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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Colligative properties
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[Post New]16 Apr 2008 08:52:08 IST
    Subject: Colligative properties
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gau.rav (14)

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The pressure of the water vapour  of a solution containg a non-volatile solute is 2% below that of the vapour of pure water.Determine the molality of the solution
    
[Post New]16 Apr 2008 11:41:04 IST
    Subject: Re:Colligative properties
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Agni2 (14)

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(Po - P)/Po = n2 / (n1+n2)
From this we can calulate n2 which is equal to 1.089 from this we can get molality which is also 1.089
The important thing is we're taking density of water as 1g/ml.
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[Post New]16 Apr 2008 12:30:26 IST
    Subject: Re:Colligative properties
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gau.rav (14)

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But answer is 1.134.please explain
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[Post New]16 Apr 2008 17:21:08 IST
    Subject: Colligative properties
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nakul2891 (0)

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yes..pls explain pls
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[Post New]16 Apr 2008 17:42:52 IST
    Subject: Re:Colligative properties
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varshavallig (798)

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P/P0  =  2/100  = n2/n1
                2/100  = n2/wt1/18
           2/18*100  =  n2/wt1
                  10/9  =n2 *1000/wt1
                    1.1  =molality
here there is an approximation of n1+n2 as n2 as given in NCERT.
rate if satisfied.
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[Post New]16 Apr 2008 18:14:46 IST
    Subject: Re:Colligative properties
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Agni2 (14)

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Ya thats right...... i didnt use that approximation
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