IIT JEE , AIEEE Forum - Physics , Electricity

gau.rav

Two charged particles ar placed at a distance 1.0 cm apart.What is the minimum possible magnitude of the elecric force acting on each charge?

ridhima

since charge is quantised ....
take the least possible charge on the charged particles ie 1.6*10^-19 c
and find the result
plz rate if it helped
edited

gau.rav

How can we take 1.6 x 10^-16

destinationIIT09

Q= +- ne

when n=1,q= +-e {this is the least possible charge as n can take only integral values as charge is quantised}

+e----------->charge on proton=1.6 *10^-19 C

-e------------>charge on electron= -1.6*10^-19 C

F = k q1 q2 / r^2

put q1 = q2 = e as the rest are constants {radius given as 0.01m}

this is the required force

smartboy198062

actually the minimum force can be zero

if u place a metal block between the 2 charges the force experienced by the 2 is zero

in the formula

1/(4

₀k) qq/r² =F

k for a metal is infinity and hence F=0

thus the minimum force between the 2 charges can be zero.

dubey

what is the potential b/w two points in a charged solid sphere of charge density sigma.?

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