See , HI is used as a reducing agent ,so It gets oxidized to I2 . this I2 is a very good oxidizing agetn . This may react with , the reactants and it may lead ot a very diff .reacn.
So , red P is added which reacts with I2 to give back , HI ,
The reacn . goes like this. (this is usually in aq . mdm.)
P + H2O ------> P2O5 + PH3
PH3 + I2 --------> HI +P
Thus I2 is prevented from reacting wiht , the reactants.
I'm not sure with the reacn.s (unbalanced) , Please coorect if wrong, I verify also later .But it definitely prevent s I2 from reacting with teh reactant mix.
That's 4 sure.