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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 19:21:39 IST
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Calculate Kb of water when 1 mole of the solute is dissolved in 1000 g of water.The latent heat of vapourisation of water is 539.9 calories per gram
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17 Apr 2008 19:40:26 IST
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use Kb =RT2M\ ( H2 --H1) *1000 R=GAS CONST. T=TEMPT H 2-- H 1 =  H M=MOLECULAR MASS USE ABOVE !!!!!!!!!!!!!!!! HOPE SATISFIED !!!!!!!!!!!!
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Kb=0.002T2/L(whereT is boiling point of water(solvent) &L is latent heat of vapourisation) rate me if u get the ans
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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17 Apr 2008 19:48:14 IST
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Not getting the answer yaar . please solve
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17 Apr 2008 19:59:34 IST
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What is the answer?the calculation is getting a bit difficult
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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17 Apr 2008 20:06:36 IST
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.514
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17 Apr 2008 20:11:51 IST
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Yes,I got the ans.substitute T=373K & L=539.9 in the above mentioned formula. (I did the calculation using calculator)
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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