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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Apr 2008 19:50:26 IST
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the number of positive integral solutions of the equation x1x2x3x4x5=1050 is_______???
plz giv detailed soln
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Apr 2008 19:52:46 IST
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I suppose everybody is very serious about VITEEE because the same question has come thrice in 3 days Here is the link
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1050=2.3.5.5.7
the answer is 1875.....
consider a,b,c,d,e as five boxes(x1,x2,x3,x4,x5)
2,3,7 can enter these boxes in 5*5*5 ways
5 can enter these boxes as two 5's or one 25 so no of ways = 5C1+5C2=15 ways
toatl no of ways = 5*5*5*15=1875 ways
so total no of solutions is 1875
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2008 22:06:41 IST
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let me give the solution for any given no ....it wud be helpful....
let n= x1x2x3.x4x5= 2^a,3^b,5^c.....
then x1 = 2^@1.3^@2.5^@3......... similarly for x2,x3,x4....
now we have @1 +%1 +.....= a total no of integral soln will give the answer........
this is a very long method but i tried it myself ...others may give shorter ways....
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