| Q) the value of integration (dx/(a2+x2)7) between d limits 0 and infinity is equal to____??? | |
 |
Sol) Substitute x=a tan
Thus dx/d
=a sec2
or dx = a sec2
d
...(1) Also, a
2+x
2=a
2(1+tan
2
)=a
2sec
2
...(2)
When x = 0,

tends to 0; and when x = infinity,

tends to

/2
Thus, Using (1) and (2) the value of integral is
I =
[ 0]
[
/2] a sec
2
d

/(a
2sec
2
)
7 or I =1/a
14 [ 0]
[
/2] cos
12
d

...(3)
Now either use the reduction formula to solve this integral or use replace

by

/2 -

, and then add the so obtained value of I to (3) to obtain 2I and simplify.