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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: moment of inertia
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amway (23)

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we have 2 spheres one of which is hollow and the other is solid they have identical masses and MI about their respective diameters the ratio of their radii is given by
    
Decoder (844)

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MI r given ??

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amway (23)

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no they r not given
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pinnacle (223)

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root 5/3
 
 
Identical mass and MI
so
2/3 MR2 = 2/5 MR'2
 
 

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amway (23)

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no the ans is not that
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pinnacle (223)

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wts d answer den dude?

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Decoder (844)

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hey pinnacle look masses r same not both radius and masses..

ok !! i give u the soln..


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Decoder (844)

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since MI r same ( language nahi samjh paya tha)..

and so r the masses...
therefore...

2/3 r^2 = 2/5 R^2...

thus r/R = root ( 3/5)

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pinnacle (223)

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Brother
we have been given dat mass and MI is same
i havnt taken radii to be same too
i hav taken dem as R and R'

I Tried So Hard And Got So Far
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It Doesnt Even Matter...
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Decoder (844)

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rite ..but see yaar !!..u forgot to take the underoot..

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RyuAmakusa (942)

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yes it should be root 3/5 or root 5/3. if the ans. is diff then. that ans. is wrong. or the question is wrong
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sarthak321 (62)

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let the two spheres have masses m and radii r and r' ( r----solid sphere,,.. r" --- hollow sphere)

for solid sphere
MI = 2/5 mr2

for hollow sphere

MI = 2/3mr"2

2/3mr"2 = 2/5mr

r"2/3 = r2/5
r"/r= (3/5)


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