(1) if ax²+bx+c =0 and a+b+c=0

than roots of that equation is

ANS:

1,c/a

1,-c/a

the ans is 1,c/a.It is obvious that one root is 1.Use product of roots to get other one as c/a

Given that f(1) = 0

That implies the other root is c/a

~Cheerio!!

1,c/a.

hey see this

given a+b+c=0

therefore

substituting in given  exprssn

ax^2+bx+(-a-b)



=a(x^2-1)+b(x-1)=0

taking( x-1) common

(x-1)(ax+a+b)=0

that implies

x=1 or  ax=-(a+b  )      

=ax=c         (given a+b+c=0)

therefore   x=c/a

therfore answer is 1, c/a

correct if i am wrong!!

By simply looking at the equations, one root comes out to be 1.

The product of the roots is c/a, hence the second root is c/a.

hey flowers,after taking (x-1) common u made a mistake.it should be (x-1)(ax+a+b)=0

so,the ans are 1,c/a

y=ax2 +bx+c=0

let x=1

a+b+c=0

this implies parabola cuts parabola when x=1

therefore one root is 1.

root1 * root 2=c/a

this implies root2 = c/a

thereforeroots r (1,c/a)

got it..