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ra (0)

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Among 20 members of a cricket club, there are two wicket-keepers and 5 bowlers. In how many ways can eleven be chosen so as to include only one of the wicket-keepers and at least three bowlers?
    
ankur.kkhurana (922)

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there wil be three cases
when there are three bowlers .-     20C16  + 2C1 + 5C3
when there are 4 bowlers   -          20C15  + 2C1 + 5C4
when there are 5
bowlers  -                 20C14  + 2C1 + 5C5

a
        add them to get ans . if u find my nas. satisfactory plz. rate it

adversities cause some men to break other to break records............i m of the other type....... :-)
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anchal_1991 (237)

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there will be three cases
when there are three bowlers .-     13C7 X 2C1 X 5C3
when there are 4 bowlers   -         13C6 X 2C1 X 5C4
when there are 5
bowlers  -               13CX 2C1 X 5C5


NOW ADD ALL OF THEM

dont worry .
be happy and positive
nd nvr stop bcz life cant wait.
nd watever happens keep smiling bcz log haste huye btr lagte hain.try to fight wid d situation
nd tc of urself bcz u r spl to someone out dere
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ankurgupta91 (828)

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aanchal is quite rght bt nt exactly
the rght ans is
when there are three bowlers :- 13C7 X 2C1 X 5C3
when there are four bowlers :- 13C6 X 2C1 X 5C4
when there are five bowlers :- 13C5 X 2C1 X 5C5
nw add all these cases nd u wl surely get the rght answer
thanku...........

nobody is perfect......i m nobody..............
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