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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 10:34:24 IST
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the equation :
3sin2x+2cos2x + 31-sin2x+2sin2x =28 is satisfied for the values of x given by:
cos x=1
tanx = -1
tanx =1
none of these
guys...... rates are assured......
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 10:46:13 IST
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is the answer tanx=1 ???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 10:55:08 IST
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none of these???
i am getting a diff answer ...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 10:58:12 IST
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yes it is none of these 
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 11:04:50 IST
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Yes,i am also getting none of these.
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28 = 27 + 1 = 3^3 + 3^0
So either : 1) sin2x + 2cos2x = 3 & 1 - sin2x + 2sin2x = 0 1 + sin2x = 0 sin2x = -1 2cos2x = 3 + 1 = 4 cos2x = 2 ....... not possible
OR
2) sin2x + 2cos2x = 0 & 1 + sin2x = 3 again here sin2x = 2 ...... not possible and cos2x = -1
SO NONE OF THESE ...
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 13:12:34 IST
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I tink ur ques is wrong why is it 3^1-sin2x+2sin2x wen it can be 3^1+sin2x
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IM NO BABY
I HAVE THE SEVENTH SENSE
NONSENSE!!!!!!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 13:13:42 IST
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exactly there is some mistake in the second exponent! :)
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 16:19:44 IST
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Please write the correct question.
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