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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 17:40:51 IST
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P IS A VARIABLE POINT ON THE ELLIPSE x2/a2+y2/b2-1=0, WITH AA’ AS THE MAJOR AXIS .THEN WHAT IS THE MAXIMUM VALUE OF THE AREA OF TRIANGLE APA’?
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When p ia at A or A' area=0, as p starts moving towards the minor axis area increases and therefore area is maximum at (0,+b) or (0,-b) -
hence area=1/2[a(b-0)+0+(-a)(0-b)=ab
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 18:36:45 IST
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Perfect answer force_IIT. As base of the triangle is fixerd you need to maximize height, which is b.
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 18:38:58 IST
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