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nandithac (86)

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an iron casting consists of cavities it wieghs 6000N in air and 4000N in water.the density of iron is 7.8g/cm3 find the volume occupied by the cavities

    
zorro (106)

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(V - Vc).7800.g = 6000 .............(1)

V.1000.g = 2000 ..............(2)

solve (1) and (2) to get Vc = 0.123 m^3

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nandithac (86)

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can u pls explain the 2nd eqn??

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Aatish (2313)

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Its a simple application of Archimedes Principle.....


 


see....from the given data.....


 


Volume of the Body =  ( Loss in weight of the body ) / (density of water x g)


 


                                  =   ( 6000 - 4000 ) / ( 0.001 kg cc-3 x 9.8 )


 


                                  =   204081.63 cc3


 


Now Volume of the material in the body = mass of body / density of material


 


= 6000 / (0.0078 kg cc-3 x 9.8)


 


= 78492.93 cc3


 


So Volume of the cavities = 204081.63 - 78492.93 = 125588.7 cc 


 


I hope there is no Calculation mistake.......


 


cheers!!!


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zorro (106)

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yup! aatish's xplanation is correct..

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nandithac (86)

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thanx guys

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