IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

golu1234

For the nonequilibrium process A + B ------------P,the reaction is of first order with respect to A and of second order with respect to B.If 1 mole each of A and B are introduced into a 1- liter flask, and the initial rates were 1 x 10^-2 moles/liter .s,Calculate the rate when half the reactants have converted to the products.

ashish_banga

is the answer 1.25 X 10^-3

budokai_tenkaichi_returns

check out dat half d initial conc is dere

so acc to ques

rate will become 1/8 of initial

golu1234

Yes, ashish ,u are right, but please explain the methods

ashish_banga

when [A] = 1 , [B] = 1
R = K = 0.01

when they are reduced to half,
R = K [A] [B]^2
put K, [A] = [B] = 1/2

budokai_tenkaichi_returns

did i did somethimg different

??

answer me

golu1234

How can the value of K can be same, it is not given in the question that the reaction is of first order

ashish_banga

K DEPENDS ONLY ON TEMPERATURE

golu1234

K depends only on temperature when the reaction is of first order.But it is not given in the question,so how can u substitute the value,please explain/

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