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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: circular motion
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prateek.agarwal (307)

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arvind1990 (305)

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angular velocity=omega=v/r!!
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prateek.agarwal (307)

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well...thats what even i thought...but the correct answer is (b)...i need 2 know y???
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jalanshruti (8)

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angular velocity is v/r from centre of circle not from pt on the circle
the pt can b fixed anywhere on circle so lrt us fix it at diametrically oppo. to body executing motion. Now body moves with radius 2r wrt that pt.
so 
 = v/2r (considering initial motion of body pure rotatory wrt fixed pt.)
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kislay (1118)

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well jalanshruti the particle will move about any point on the circle with radius as 2r if its is always diametrically oppo.to the fixed point .but the case is diff.

Here is correct solution.
Let the angular velocity of any body in circular motion be  about the center of circle .but d/dt of the particle about any point on the circle is equal to /2(any arc subtends
on the centre twice the angle subtended at any point on the circle )
=v/r(about centre)

/2=v/2r.(about any pt. on circle)
please rate me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!


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arun.k.iit (7)

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=V/R

WHERE R IS THE RADIUS OF THE CIRCLE

HERE R=2r
SO    =V/2r

PLS RATE

ARUN

TRY,TRY,TRY TILL U SUCCEEEEEEEEEEEEEEEEEEED
YOU CAN DO WHATEVER U WANT,JUST TRY

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prateek.agarwal (307)

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hey kislay...i think ur right...i never thought of this in that way...plz tell me have u done this earlier and i'll give u a salute...
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kislay (1118)

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no prateek i had not done that before.pls rate!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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prateek.agarwal (307)

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thnx man...rated u...
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