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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 May 2008 08:29:29 IST
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Capillary tube sealed at the top has an internal radius of 0.05cm.The tube is placed verically in water,open end first.What should be the length of such a tube for the water column to rise in it to a length of 1 cm? Surface tension of water = 70 X  N/m.
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10 May 2008 23:07:09 IST
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A straight forward sum that makes use of the formula:
S = Surface Tension of the liquid, r = inner radius of the capillary tube, etc. So go ahead!
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11 May 2008 00:10:19 IST
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Since the tube is sealed at the top, so the pressure above water level in the tube will be zero .
hence we can't use the formula : h=2Scos(theta)/rpg .
So, Let W be the weight , S be the surface tension and P be the pressure at the bottom of the capillary tube in level with the water surface, then
W = (pie)*r^2 h*p*g
At equilibrium,
W = P*(pie)* r^2 + 2*(pie)* r*S
put the values and get the answer.....
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11 May 2008 03:32:16 IST
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Oh yes, good work. I made a grave mistake there.
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25 May 2008 12:36:12 IST
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thanx.....
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