2 heavy bodies in d form of solid spheres each of mass M &radius R are at initial separatn of 6R..........so find d value of speed V which is givn to 1 body in a direction perpendicular to d line joining dem,,,,so dat dey r just able to touch each odr....

one sphere will revolve around the other so we have to balance the gravitational force between the spheres with the centripetal for THE SPHERE.

(GM.M)/36R²>(MV²)/R

V<(GM/6R)^1/2

^{TELL ME IF I M RIGHT}.

Firstly, I am assuming that the two bodies are in vaccum. In that case, the other body doesn't remain stationary. It will also move. The calculation based on a circular motion of the sphere to which velocity is given is incorrect. Let us solve the problem in the reference frame of the sphere which isn't given a velocity. It also accelerates. So its an non inertial reference frame. Then we must apply the modified form of Newtons second law

where is the reduced mass of the system, and as the masses are equal, its equal to m/2

Rearrange and integrate this equation and integrate for v from V to 0, and for x from 6R to 4R

sir plz can u tell me the concept of reduced mass