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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 May 2008 23:39:32 IST
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A beaker contains water =4/3 filled to a ht of 32 cms.A concave mirror is fixed 6 cm above the surface of water. An object is placed at the bottom of the beaker & its image is formed14 cms below the surface of water. The focal lenght of the mirror
8
12
16
20
ans is 12cm
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 May 2008 23:47:04 IST
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12cm
apparent depth of the object = real depth/mu = 24cm now object distance from the mirror = 24 + 6 = 30 cm image distance from the mirror = 14 + 6 = 20cm use mirror equation now with sign u will get f = -12cm
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