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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 10:13:53 IST
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how can the acceleration of the body is constant if velocity be 0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 10:17:52 IST
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vel =0
acc=0
0 is a constant buddy
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SAIYANS ARE OF TRUE WARRIOR RACE . DONT UNDER-ESTIMATE US!
special theory of relativity ....i luv it...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 10:28:29 IST
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It can be.Take the case of body thrown upwards,its velocity at highest point is 0 but still its acceleration is g directed downwards which is constant throughout its motion.
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"Nenenthedhavano naake teleedu"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 10:51:01 IST
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a=dv/dt. , a can be zero if v does not change over a time interval dt. zero is a constant too.
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xxxxxxxxxxxxxxx Dylan João Colaço .xxxxxxxxxxxxxx |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 10:56:56 IST
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yes he is right a
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 12:56:27 IST
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acceleration is defined as the rate of change of velocity with respect to time
if velocity is constant(0 is a constant), it means that change in velocity is zero and so is the rate of change of it i.e. acceleration=0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 14:49:59 IST
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it is possible when a body is momentarily at rest ,, for example abody thrown vertically upwards has zero vel but definite acc.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 19:21:00 IST
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a body thrown vertically upwards has zero vel but definite acc.
Can u xplain plz............??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 19:23:42 IST
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@ rtit :
when a body is thrown upwards then at the highest point the velocity becomes zero but still the gravitational acceleration acts on it and it is constant. so acceleration is definite where as the velocity is zero.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2008 19:24:28 IST
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see dude acceleration is dv/dt and as v=0, dv/dt is a constant which is acceleration...hence accl is constant...and for u rtiit i think its coz of the g acting downwards....so accl is definite...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 May 2008 21:46:02 IST
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hey,
velocity is a theoritical concept which is a vector quantity...
there can be instance when vel. is 0 but speed is not 0 hence accelleration will not neccessary b 0
it IS A THEROTICAL CONCEPT
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 May 2008 22:44:43 IST
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IT IS SIMPLE IN THIS SITUATION V=U A=V-U/T=0/T=0 ACC IS CONSTANT COZ THE FINAL VELOCITY = INITIAL VELOCITY AT ALL TIMES IN OTHER WORDS SINCE ACC IS 0 AT ALL TIMES IT IS CONSTANT SIMPLE PLZ RATE ME IF U FIND ME USEFUL !!!!!!CHEERS!!!!!!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 May 2008 22:46:19 IST
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@ varun :
it is not necessary that acceleration is 0 so it is constant ...
in every case u cant say that
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 May 2008 23:28:31 IST
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if V is 0 den dv/dx is 0.difeerentail of a constant is o so A is constant.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 00:22:23 IST
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When acceleration is constant(not zero) then only instantaneous velocity (dx/dt) can be zero but not the velocity for an extended time period. Take for example the case of a body thrown upwards, its velocity at the top most point is zero(instantaneously) although it has constant acceleration 'g' .
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