WHAT IS THE DINESION OF C IN:

D=A+D/C^2

D=DENSITY

A=AREA

D= A CONSTANT

PLZZZZZ HELP IT IS BUZZZIN ME

I THINK C= TO [M^1L^-3]

C= ML^-3

how is this possible



[ D] = [ D/C^2]

then

c^2 must be dimensionless

the question is wrong i guess

according to question

[D] = [A]

which is impossible

*edited.....THANKS ganesha1991

d=A+D/C^2



d is a constant having dimensions of L^2





so,...D/C^2 should also have dimensions of L^2....so C^2 gets the dimensions of M L^(-5)...C has dimensions of M^(1/2) L^(-5/2)



hope it helps...cheero :)

CASE 1





The Question is:    d   =   A  +  ( D / C² )    where 'd' is the constant with dimensional formula [ L² ].

So, the dimensions of  ( D / C² )  =  Dimensions of A  =  [ L² ].

Therefore, the dimensions of C²  =  Dimensions of  ( D / A )  =  [ M L ^{- 5} ]

==> Dimensions of C  =  [ M^1/2 L ^{- 5/2} ]

CASE 2





The Question is:    D  =  ( A + d ) / C²    where 'd' is the constant with dimensional formula [ L² ].

So, the dimensions of C²  =  Dimensions of  ( A + d ) / D  =  [ L² ] / [ M L^{- 3} ]  =    [ M ^-1 L⁵ ].

==> Dimensions of C  =  [ M ^-1/2 L^5/2 ]