WHAT IS THE DINESION OF C IN:

D=A+D/C^2

D=DENSITY

A=AREA

D= A CONSTANT

the first D cannot be density

if its density then  according to dimensions formula will be wrong because  [D] cannot be equal to [A]

so the formule is

d = A + D/C^2

[A] = [d]

here d is the constant



so dimension of constant d = L^2



now

[d] =[ D/C^2]

C^2 = ML^-3 / L^2



C^2 = ML^-5

[C] = M L^-5/2

Good answer @ganesha1991

CASE 1

The Question is:    d   =   A  +  ( D / C² )    where 'd' is the constant with dimensional formula [ L² ].

So, the dimensions of  ( D / C² )  =  Dimensions of A  =  [ L² ].

Therefore, the dimensions of C²  =  Dimensions of  ( D / A )  =  [ M L ^{- 5} ]

==> Dimensions of C  =  [ M^1/2 L ^{- 5/2} ]

CASE 2

The Question is:    D  =  ( A + d ) / C²    where 'd' is the constant with dimensional formula [ L² ].

So, the dimensions of C²  =  Dimensions of  ( A + d ) / D  =  [ L² ] / [ M L^{- 3} ]  =  [ M ^-1 L⁵ ].

==> Dimensions of C  =  [ M ^-1/2 L^5/2 ]