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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Differential Calculus .
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neil_mahaseth (5)

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Differential Calculus .






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aditi_g (355)

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4. let 2/sqrt 13 be cos @ thn 3/sqrt13 becomes sin@
so the given expression becomes cos ` (cos( x-@)) = x-@
but this is true if <0x-@owise the expressn wud be pi -(x-@)
therefore @< xand @ = tan inv 3/2
so option D) is rite
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aditi_g (355)

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2) ie . Q20

ist put x=0 u get y= ae^pi/2

take log on both sides



write it as 1/2 log(x^2+y^2)


now differentiate and simplify


ull get x+y dy/dx = x dy/dx - y


x+y= (x-y)dy/dx ..............1)


put x=0 dy/dx = -1


now differentiate eqn 1) again


1+dy/dx = (1-dy/dx)dy/dx + (x-y) d^2y/dx^2


put x=0,also whn x=0 dy/dx=-1 and y= a e^pi/2


put all the values ull get d^2/dx^2 = -2/a(e ^ -pi/2)


i hope its clear


 


 

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rohit_08_vns (12)

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i think ans of Q.1 is -1


reply me about correct answer

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nunknown91 (66)

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q 1 )




hence



<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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allamraju (3422)

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For q29)Is the ans sin.I will explain if correct.

MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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