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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 19:58:05 IST
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insted gimme d link
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doceed ti u nac ? |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 20:00:30 IST
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yaar mera mouse kharaab hai to thodi problem hai....just do as i said.....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 20:02:08 IST
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are type kya karna hai ...
and all wat i said ...(i m sorry for dat)
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doceed ti u nac ? |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 20:03:14 IST
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and yeahh,..
even my mouse isnt that gr8
i can understand ur link--copying problem
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doceed ti u nac ? |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 20:04:01 IST
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arey koi baat nahi dude....waise did u see the solution.....it was great mind work.....heehee
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 20:05:26 IST
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i wud luv to talk to u ...
but i gotta go ...
(arre ..room thikk karna hai ..papa aane wale hain )
bye ..friend .
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doceed ti u nac ? |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 20:10:06 IST
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ok....bye dost
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 May 2008 23:21:57 IST
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Put it in the indian politics way,
''The enemy of their enemy is their FRIEND'' therefore, -ve(enemy) x -ve(enemy) = +ve(friend).
Hope i m understood by u.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 May 2008 14:16:35 IST
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nw let me give all u guys a good solution of this problem... let x= (a)(b) + (-b)(a) +(-a)(-b) = a(b-b) + (-a)(-b) = 0 + (-a)(-b) also x=ab + (-b)(a-a) = ab +0. so ab = (-a)(-b)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 May 2008 16:56:18 IST
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this can be explained on the basis of iota(i) where i=(-1)1/2
(( -ve x -ve)4)1/4 =(i4)1/4 =11/4 = 1
hence resultant is positive.
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