IIT JEE , AIEEE Forum - Physics , Electricity

manja

can the feild due to a conducting cone having a charge Q be found using gauss law? how?

indrajeet_bariar

I DONT THINK IT CAN BE FOUND OUT BY USING GAUSS LAW COZ. FOR APPLYING GAUSS LAW WE HAVE TO MAKE A GAUSSIAN SURFACE AND THE REQUIREMENT FOR THE SURFACE IS THT EACH POINT ON IT MUST HAVE SAME ELECTRIC FIELD FOR WHICH A SYMMETRRIC SURFACE IS REQUIRED AND FOR CONE I DONT THINK SUCH A SURFACE IS POSSIBLE.

animal

yes the electric field due to a conducting cone can be found if the electric field is perpendicular to its base(circle)

then $\phi$ =E. $\pi$ r²(area of base circle)

E= $\phi$ / $\pi$ r²

hope u got it.

indrajeet_bariar

N HOW COME ELECTRIC FIELD PERPENDICULAR WHEN IT IS UNIFORMLY DISTRIBUTED THROUGHOUT THE SURFACE OF THE CONE.wHT ABT THE REST SURFACE OF GAUSSIAN SURFACE.R U TRYING TO SAY THT FLUX THROUGH THEM WILL BE ZERO???

indrajeet_bariar

JUST TELL ME WHT KIND OF GAUSSIAN SURFACE U R USING???

indrajeet_bariar

@animal
HEY DUDE, WHY R U NOT GIVING ME REPLY. I M CURIOUS TO KNOW THE METHOD.

manja

animal,

i think u have forgotten the curved surface

indrajeet_bariar

right manja.thts wht i was saying. how come the curved surface is not taken into account coz. in tht case the electric field will not be same at all the points and hence GAUSS thoerum cant be applied as the E will not come out of the integral.

islahul_101

well the best method is to divide the cone into two halves u get a triangle and a half circle thru wich flux is damn easy to find!! that flux is half of total flucx thru curved srfaces

tiya

i thnk indrajeet ws correct ....it is nt possible 2 construct gaussian surface here........

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