two identical small balls, each of mass m amd having charge q are suspended by two light inelastic conducting threads each of length l from the same fixed pont support. if the distanced between the two balls is vey less, then d is equal to?
If d is distance between them then, assume angle between strings is theta theta= d/l Tcos(theta/2)=mg Tsin(theta/2)= kq^2/d^2 For small angle cos(theta/2)=1 sin(theta/2)=d/2l So mgd/2l=kq^2/d^2 So d=(2kq^2l/mg)^(1/3)
Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi