2^x+2^y=2^x+y,then dy/dx is equal to

Differentiating on both sides w.r.t x,

2^xln2+2^yln2.y'=2^x+yln2(1+y')

2^x-2^x+y=y'(2^x+y-2^y).But 2^x+y=2^x+2^y,substituting this,we get,y'=-2^y/2^x=-2^y-x

2^xlog2+2^ylog2 dy/dx=2^x+ylog2(1+dy/dx)

2^x+2^y dy/dx=2^x+y(1+dy/dx)

solve and subsitute for 2^x+y=2^x+2^y

or there are many ans in case of diffrentiation.......go from ans to guesONLY IN CASE OF NEED