IIT JEE , AIEEE Forum - Mathematics , Algebra

man111

(1) if IIxI-4I = a has only one solution than find he value of a.

svj29

dude one simple method:

draw the graph of y=IIxI-4I, and then the graph of y=a

and see where only one intersection point will be there, that will be the desired point :)

allamraju

The ans I got is a does not exist,

a<0 $\Rightarrow$ no soln.

a=0 $\Rightarrow$ two solns.

0<a<4 $\Rightarrow$ four solns.

a=4 $\Rightarrow$ three solns.

a>4 $\Rightarrow$ two solns.

It becomes more easy if u plot the graph correctly.It will be like a W.

animal

i m not confident still i m trying

IIxI-4I=a has only one soln is given

we know that it can always have 2 values of x for 1 a one +ve and 1 -ve.

but as it is given to have 1 soln and not 2

therefore x=0

putiing x=0 we get

a=4

tell me if i m right.

spideyunlimited

if a = 4, then x can be 8, or -8. or 0

animal

yes spidey u r right

then I would also go with allamraju that there is no such a.

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The ans I got is a does not exist,

a<0no soln.

a=0two solns.

0<a<4four solns.