Let The point below P in plane of eyes of prisioner at A and B is Q Let PQ=h and AQ=b From first tan(31)=h/b By pythagorus theorm BQ=sqrt(b^2+15^2) Therefore tan(25)=h/sqrt(b^2+15^2)
Using the two equations solve for h and b. Height of point P=h+1.7 meters
Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi