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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 23:48:17 IST
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First problem:
x2 + 4y2 + 5 = 4z
x-y >or= z
Second problem:
x + (1/y) = 1
xy2 + (1/x2y) = 1 + (y/x)
How to solve the above two problems?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 21:24:27 IST
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For the first one substitute the value of z in the first equation.. It'll represent an area on the x, y plane and the solid corresponding to in 3-d space..
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