integration1/root(x-a)(b-x)   dx

The standard method to solve integrals of this type is to put x=acos²k+bsin²k.Try and tell me if u don't get,I will post the complete soln.

we can also do by mutiplying by (b-a) and breaking it in terms of denominator

hey this is another method:



since here discriminant is greater than zero and x^2 coeff is less than zero



use the method



I = [1/root(-a )*{ sin^-1 (-d/dx (lx^2+mx+n)/root over discriminant]}







where l=-1



m=(a+b)



n=-ab